页面显示如下：
JQueryAjax.html中的代码如下（用的较为简单的$.post）
[html]view plaincopy print? <html> <head> <meta charset="UTF-8"> <title>JQueryAjax+PHP</title> <script type="text/javascript" src="/jquery-3.0.0.min.js"></script> </head> <body> 用户名:<input type="text" id="username" name="username" /><br> 密码:<input type="password" id="password" name="password" /><br> <button type="button" class="butn">ajax提交</button><br> <span class="con"></span> <script type="text/javascript"> $(document).ready(function(){ $(".butn").click(function(){ var username = $("#username").val(); var password = $("#password").val(); $.post('ajax.php',{name:username,pwd:password},function(data) { alert(data); $(".con").html(data); }) })})</script> </body> </html>
<html><head><meta charset="UTF-8"><title>JQueryAjax+PHP</title><script type="text/javascript" src="/jquery-3.0.0.min.js"></script></head><body>用户名:<input type="text" id="username" name="username" /><br>密码:<input type="password" id="password" name="password" /><br><button type="button" class="butn">ajax提交</button><br><span class="con"></span><script type="text/javascript">$(document).ready(function(){$(".butn").click(function(){var username = $("#username").val();var password = $("#password").val();$.post('ajax.php',{name:username,pwd:password},function(data) {alert(data);$(".con").html(data);})})})</script></body></html>
ajax.php：
[php]view plaincopy print? ajax.php<?phpecho '用户名:',$_POST['name'],',密码：',$_POST['pwd']."<br>"; //这里可以进行一些操作，比如数据库交互 echo "操作完毕"; ?>
ajax.php<?php echo '用户名:',$_POST['name'],',密码：',$_POST['pwd']."<br>";//这里可以进行一些操作，比如数据库交互echo "操作完毕";?>
在非json格式下，后台只能返回字符串，如果想后台返回数组，可以采用json格式
例如将JQueryAjax中的代码修改为如下形式：
[html]view plaincopy print? <html> <head> <meta charset="UTF-8"> <title>JQueryAjax+PHP</title> <script type="text/javascript" src="/jquery-3.0.0.min.js"></script> </head> <body> 用户名:<input type="text" id="username" name="username" /><br> 密码:<input type="password" id="password" name="password" /><br> <button type="button" class="butn">ajax提交</button><br> <span class="con"></span> <script type="text/javascript"> $(document).ready(function(){ $(".butn").click(function(){ var username = $("#username").val(); var password = $("#password").val(); $.ajax({ url: "ajax.php", type: "POST", data:{name:username,pwd:password}, dataType: "json", error: function(){ alert('Error loading XML document'); }, success: function(data,status){//如果调用php成功 alert(status); alert(data); $('.con').html("用户名:"+data[0]+"密码:"+data[1]); } }); })})</script> </body> </html>
<html><head><meta charset="UTF-8"><title>JQueryAjax+PHP</title><script type="text/javascript" src="/jquery-3.0.0.min.js"></script></head><body>用户名:<input type="text" id="username" name="username" /><br>密码:<input type="password" id="password" name="password" /><br><button type="button" class="butn">ajax提交</button><br><span class="con"></span><script type="text/javascript">$(document).ready(function(){$(".butn").click(function(){var username = $("#username").val();var password = $("#password").val();$.ajax({url: "ajax.php", type: "POST",data:{name:username,pwd:password},dataType: "json",error: function(){ alert('Error loading XML document'); }, success: function(data,status){//如果调用php成功 alert(status);alert(data);$('.con').html("用户名:"+data[0]+"密码:"+data[1]);}});})})</script></body></html>
ajax.php
[php]view plaincopy print? <?php$name = $_POST['name']; $pwd = $_POST['pwd']; $array = array("$name","$pwd"); //这里进行一个些操作，比如数据库交互 echo json_encode($array);//json_encode方式是必须的 ?>
<?php $name = $_POST['name'];$pwd = $_POST['pwd'];$array = array("$name","$pwd");//这里进行一个些操作，比如数据库交互echo json_encode($array);//json_encode方式是必须的?>
运行效果如下：
/qq_28602957/article/details/51814437
