wordpress的文章点赞方法很多，而且大多数都是依赖插件，插件多的话，网站打开速度较慢。所以分享出来一款非常简洁的纯代码实现wp主题点赞的功能。并且运用cookies有效的解决了重复点赞bug。
1、在functions.php文件中添加点赞方法：
add_action('wp_ajax_nopriv_yd24_goods', 'yd24_goods');
add_action('wp_ajax_yd24_goods', 'yd24_goods');
function yd24_goods(){
$id = $_POST["um_id"];
$action = $_POST["um_action"];
if ( $action == 'click'){
$yd24_raters = get_post_meta($id,'yd24_click',true);
$expire = time() + 99999999;
$domain = ($_SERVER['HTTP_HOST'] != 'localhost') ? $_SERVER['HTTP_HOST'] : false;
setcookie('yd24_click_'.$id,$id,$expire,'/',$domain,false);
if (!$yd24_raters || !is_numeric($yd24_raters)) {
update_post_meta($id, 'yd24_click', 1);
}else {
update_post_meta($id, 'yd24_click', ($yd24_raters + 1));
}
echo get_post_meta($id,'yd24_click',true);
}
die;
}
2、在头部引用jquery-1.11.3.min.js或者jquery其他版本
3、在头部或尾部添加ajax
$(document).ready(function() {
$.fn.postLike = function() {
if ($(this).hasClass('done')) {
alert('您已赞过本博客！');
return false;
} else {
$(this).addClass('done');
var id = $(this).data("id"),
action = $(this).data('action'),
rateHolder = $(this).children('.count');
var ajax_data = {
action: "yd24_goods",
um_id: id,
um_action: action
};
$.post("/wp-admin/admin-ajax.php", ajax_data,
function(data) {
$(rateHolder).html(data);
});
return false;
}
};
$(document).on("click", ".favorite",
function() {
$(this).postLike();
});
});
4、添加前台点赞的调用代码：
class="favorite<?php if(isset($_COOKIE['yd24_click_'.$post->ID])) echo ' done ';?>">赞
<?php if( get_post_meta($post->ID,'yd24_click',true) ){
echo get_post_meta($post->ID,'yd24_click',true);
} else {
echo '0';
}?>
5、参考CSS样式方便大家操作：
.post-like{
text-align:center;
padding:10px
}
.post-like a{
background-color:#21759B;
border-radius: 3px;
color: #FFFFFF;
font-size: 12px;
padding: 5px 10px;
text-decoration: none;
outline:none
}
.post-like a.done, .post-like a:hover{
background-color:#eee;
color:#21759B;
}
.post-like a.done{
cursor:not-allowed
}
