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Java多线程之线程通信之生产者消费者阻塞队列版

时间:2021-05-09 22:34:31

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Java多线程之线程通信之生产者消费者阻塞队列版

Java多线程之线程通信之生产者消费者传统版和阻塞队列版

目录

线程通信之生产者消费者传统版线程通信之生产者消费者阻塞队列版

1. 线程通信之生产者消费者传统版

题目: 一个初始值为零的变量,两个线程对其交替操作,一个加1一个减1,来五轮

1.代码实现

import java.util.concurrent.locks.Condition;import java.util.concurrent.locks.Lock;import java.util.concurrent.locks.ReentrantLock;class ShareData {//资源类private int number = 0;private Lock lock = new ReentrantLock();private Condition condition = lock.newCondition();public void increment() throws Exception {lock.lock();try {//1.判断while (number != 0) {//等待,不能生产condition.await();}//2.干活number++;System.out.println(Thread.currentThread().getName() + "\t" + number);//通知唤醒condition.signalAll();} catch (Exception e) {e.printStackTrace();} finally {lock.unlock();}}public void decrement() throws Exception {lock.lock();try {//1.判断while (number == 0) {//等待,不能生产condition.await();}//2.干活number--;System.out.println(Thread.currentThread().getName() + "\t" + number);//通知唤醒condition.signalAll();} catch (Exception e) {e.printStackTrace();} finally {lock.unlock();}}}/*** 题目:* 一个初始值为零的变量,两个线程对其交替操作,一个加1一个减1,来五轮* <p>* 1.线程 操作(方法) 资源类* 2.判断 干活 通知* 3.防止虚假唤醒*/public class ProdConsumer_TraditionDemo {public static void main(String[] args) {ShareData shareData = new ShareData();new Thread(() -> {for (int i = 1; i <=5 ; i++) {try {shareData.increment();} catch (Exception e) {e.printStackTrace();}}},"AA").start();new Thread(() -> {for (int i = 1; i <=5 ; i++) {try {shareData.decrement();} catch (Exception e) {e.printStackTrace();}}},"BB").start();}}

2.编译结果

2. 线程通信之生产者消费者阻塞队列版

题目: 一个初始值为零的变量,两个线程对其交替操作,一个加1一个减1,来五轮

1.代码实现

import java.util.concurrent.ArrayBlockingQueue;import java.util.concurrent.BlockingQueue;import java.util.concurrent.TimeUnit;import java.util.concurrent.atomic.AtomicInteger;class MyResource {private volatile boolean FLAG = true; //默认开启,进行生产+消费private AtomicInteger atomicInteger = new AtomicInteger();BlockingQueue<String> blockingQueue = null;public MyResource(BlockingQueue<String> blockingQueue) {this.blockingQueue = blockingQueue;System.out.println(blockingQueue.getClass().getName());}public void myProdu() throws Exception {String data = null;boolean retValue;while (FLAG) {data = atomicInteger.incrementAndGet() + "";retValue = blockingQueue.offer(data, 2L, TimeUnit.SECONDS);if (retValue) {System.out.println(Thread.currentThread().getName() + "\t 插入队列" + data + "成功");} else {System.out.println(Thread.currentThread().getName() + "\t 插入队列" + data + "失败");}try {TimeUnit.SECONDS.sleep(1);} catch (InterruptedException e) {e.printStackTrace();}}System.out.println(Thread.currentThread().getName() + "\t 大老板叫停了,表示FLAG=false,生产动作结束");}public void myConsumer() throws Exception {String result = null;while (FLAG) {result = blockingQueue.poll(2L, TimeUnit.SECONDS);if (null == result || result.equalsIgnoreCase("")) {FLAG = false;System.out.println(Thread.currentThread().getName() + "\t 超过2秒钟没有取到蛋糕,消费退出");System.out.println();System.out.println();return;}System.out.println(Thread.currentThread().getName() + "\t 消费队列蛋糕" + result + "成功");}}public void stop()throws Exception{this.FLAG = false;}}/****/public class ProdConsumer_BlockQueueDemo {public static void main(String[] args) throws Exception {MyResource myResource = new MyResource(new ArrayBlockingQueue<>(10));new Thread(() -> {System.out.println(Thread.currentThread().getName() + "\t 生产线程启动");try {myResource.myProdu();} catch (Exception e) {e.printStackTrace();}}, "Prod").start();new Thread(() -> {System.out.println(Thread.currentThread().getName() + "\t 消费线程启动");System.out.println();System.out.println();try {myResource.myConsumer();System.out.println();System.out.println();} catch (Exception e) {e.printStackTrace();}}, "Consumer").start();try {TimeUnit.SECONDS.sleep(5);} catch (InterruptedException e) {e.printStackTrace();}System.out.println();System.out.println();System.out.println();System.out.println("5秒钟时间到,大老板main线程叫停,活动结束");myResource.stop();}}

执行结果

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