#include <iostream>using namespace std;double power(double x, int n) {double val = 1.0;while (n--) {val *= x;}return val;}void main() {cout << "请输入一个八位二进制数" << endl;double sum = 0;for (int i = 1; i <= 7; i++) {char num;cin >> num;if (num == '1') { //未加单引号时,结果始终为0,加了之后就运行正常了(由于char函数设置的类型不同)double s = power(2, 8 - i);sum += s;}}cout << "转换为十进制为:" << sum << endl;return;}
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