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C语言链表求解多项式乘法问题

时间:2020-11-25 15:57:01

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C语言链表求解多项式乘法问题

C语言链表求解多项式乘法问题

解决多项式乘法问题最容易想到的就是将乘法运算转换为加法运算。从p1的第一项开始,依此乘以p2的每一项,合并同类项后放入结果多项式中。然而项数太多时,合并同类项的过程过于复杂……

此处采用的是一种逐项插入的算法,即将p1的当前项与p2的当前项相乘,并插入结果多项式中。关键是要找对插入位置。该算法中,用p1的第一项乘以p2得到初始结果多项式。

由于是按照指数递减的顺序输入的,因而读取的p1与p2也均是指数递减的多项式。相比第一种算法的合并同类项,在已排好序的情况下,逐项插入显然方便许多。

#include<stdio.h>#include<stdlib.h>typedef struct PolyNode* Polynomial;struct PolyNode {int coefficient;int expon;Polynomial next;};void Attach(int c, int e, Polynomial* p) //在p后面添加结点{Polynomial temp = (Polynomial)malloc(sizeof(struct PolyNode));temp->coefficient = c;temp->expon = e;temp->next = NULL;(*p)->next = temp;(*p) = temp;}Polynomial ReadPoly() //读取并构建多项式{Polynomial p, rear, temp;int c, e, N;p = (Polynomial)malloc(sizeof(struct PolyNode));p->next = NULL;rear = p;scanf_s("%d", &N); //读入多项式项数,注:按照指数递减的顺序输入while (N--){scanf_s("%d %d", &c, &e);Attach(c, e, &rear);}temp = p; //删除临时生成的头结点;p = p->next;free(temp);return p;}Polynomial initPoly(Polynomial p1, Polynomial p2)//用p1第一项乘以p2初始化结果多项式{Polynomial p, t, rear;p = (Polynomial)malloc(sizeof(struct PolyNode));p->next = NULL;t = (Polynomial)malloc(sizeof(struct PolyNode));t = p2;rear = p;while (t){Attach((p1->coefficient) * (t->coefficient), p1->expon + t->expon, &rear);t = t->next;}return p; //此时返回的多项式含头结点}Polynomial Mult(Polynomial p1, Polynomial p2){Polynomial p3 = initPoly(p1, p2);Polynomial t1, t2, rear, temp;int c, e;t1 = p1->next;while (t1){rear = p3;t2 = p2;while (t2){c = (t1->coefficient) * (t2->coefficient);e = (t1->expon) + (t2->expon);while ((rear->next) && (rear->next->expon > e)) //移动rear,找到插入位置{rear = rear->next;}if ((rear->next) && (rear->next->expon == e)) //合并同类项{if (rear->next->coefficient + c) {rear->next->coefficient += c;}else //同类项系数为0,删去该结点{temp = rear->next;rear->next = temp->next;free(temp);}}else//不能合并同类项即插入结点{temp = (Polynomial)malloc(sizeof(struct PolyNode));temp->coefficient = c;temp->expon = e;temp->next = rear->next;rear->next = temp;}t2 = t2->next;}t1 = t1->next;}temp = p3;p3 = p3->next;free(temp);return p3;}void PrintPoly(Polynomial p) //输出多项式{Polynomial ptr;ptr = p;if (!ptr)printf("0\n");while (ptr->next){printf("%dx^%d + ", ptr->coefficient, ptr->expon);ptr = ptr->next;}printf("%dx^%d\n", ptr->coefficient, ptr->expon);}int main(){Polynomial p1, p2, result;p1 = ReadPoly();p2 = ReadPoly();result = Mult(p1, p2);printf("多项式1为:\n");PrintPoly(p1);printf("多项式2为:\n");PrintPoly(p2);printf("两式相乘结果为:\n");PrintPoly(result);return 0;}

(代码可直接运行)

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