C语言实现简单的五子棋代码

#define _CRT_SECURE_NO_WARNINGS// VS添加这个宏，关闭C4996报错#include <stdio.h>#define N 16 // 定义棋盘大小//显示五子棋棋盘void wzq_show(char(*GAME)[N]){int i = 0, j = 0;printf("五子棋棋盘如下：\n");for (i = 0; i<N; i++){for (j = 0; j<N; j++){printf("%c ", GAME[i][j]);}printf("\n");}}//初始化五子棋棋盘void wzq_init(char(*GAME)[N]){int i = 0, j = 0;for (i = 0; i<N; i++){for (j = 0; j<N; j++){GAME[i][j] = '+';}}//memset(GAME,'+',N*N);}//游戏是否胜利的运算,一旦有人胜利则返回1int wzq_play(int a, int b, char(*GAME)[N]){char qizi = GAME[a][b];int i = 0, j = 0, k = 0;//方向-上的for (j = b - 4; j<b + 4; j++){if (j<0 || j>N - 1){continue;}for (i = 0; i<5; i++){//if ('@' == GAME[a][j + i] || '+' == GAME[a][j + i])if ('+' == GAME[a][j + i]){break;}if (qizi == GAME[a][j + i] && 4 == i){printf("\n恭喜你，－方向上完成五子连珠!\n");return 1;}}}//方向|上的for (i = a - 4; i<a + 4; i++){if (i<0 || i>N - 1){continue;}for (j = 0; j<5; j++){//if ('@' == GAME[i + j][b] || '+' == GAME[i + j][b])if ('+' == GAME[i + j][b]){break;}if (qizi == GAME[i + j][b] && 4 == j){printf("\n恭喜你，｜方向上完成五子连珠!\n");return 1;}}}//方向\上的for (i = a - 4, j = b - 4; i<a + 4 && j<b + 4; i++, j++){if (i<0 || i>N - 1 || j<0 || j>N - 1){continue;}for (k = 0; k<5; k++){//if ('@' == GAME[i + k][j + k] || '+' == GAME[i + k][j + k])if ('+' == GAME[i + k][j + k]){break;}if (qizi == GAME[i + k][j + k] && 4 == k){printf("\n恭喜你，＼方向上完成五子连珠!\n");return 1;}}}//方向/上的for (i = a + 4, j = b - 4; i>a - 4 && j<b + 4; i--, j++){if (i<0 || i>N - 1 || j<0 || j>N - 1){continue;}for (k = 0; k<5; k++){//if ('@' == GAME[i - k][j + k] || '+' == GAME[i - k][j + k])if ('+' == GAME[i - k][j + k]){break;}if (qizi == GAME[i - k][j + k] && 4 == k){printf("\n恭喜你，/ 方向上完成五子连珠!\n");return 1;}}}return 0;}int main(){char GAME[N][N] = { 0 };int count = 0;//轮换落子计算int m = 0, n = 0;//白家int x = 0, y = 0;//黑家int res = 0;int k = 0;wzq_init(GAME);wzq_show(GAME);while (1){//当棋盘格子被下满了时if (N*N == count){printf("棋盘已经下满了，平局!\n");return 0;}if (0 == count % 2){printf("请白家落子（例如0 3或1 3）：");scanf("%d%d", &m, &n);while (m<0 || m>N - 1 || n<0 || n>N - 1){printf("输入的坐标超出范围，请重新输入：");scanf("%d%d", &m, &n);}while ('+' != GAME[m][n]){printf("此处已经落过子，请重新落子：");scanf("%d%d", &m, &n);}GAME[m][n] = 'O';res = wzq_play(m, n, GAME);if (1 == res){wzq_show(GAME);printf("白方胜！程序结束\n");return 0;}}else{printf("请黑家落子（例如0 3或1 3）：");scanf("%d%d", &x, &y);while (m<0 || m>N - 1 || n<0 || n>N - 1){printf("输入的坐标超出范围，请重新输入：");scanf("%d%d", &m, &n);}while ('+' != GAME[x][y]){printf("此处已经落过子，请重新落子：");scanf("%d%d", &x, &y);}GAME[x][y] = '@';res = wzq_play(x, y, GAME);if (1 == res){wzq_show(GAME);printf("黑方胜！程序结束\n");return 0;}}count++;wzq_show(GAME);}}

之前写的没检查，存在只有白方胜出的bug，现在改一下重新上传。这个五子棋是两人下，核心在于游戏结束的判断，而判断也仅是几个循环，并无太大难度。适合初学者玩玩