# -*- coding: utf-8 -*-def Num2MoneyFormat(change_number):""".转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 )change_number 支持 float, int, long, string"""format_word = ["分", "角", "元","拾", "百", "千", "万","拾", "百", "千", "亿","拾", "百", "千", "万","拾", "百", "千", "兆"]format_num = ["零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"]if type(change_number) == str:# - 如果是字符串,先尝试转换成float或int.if '.' in change_number:try:change_number = float(change_number)except:'%s can\'t change' % change_numberelse:try:change_number = int(change_number)except:'%s can\'t change' % change_numberif type(change_number) == float:real_numbers = []for i in range(len(format_word) - 3, -3, -1):if change_number >= 10 ** i or i < 1:real_numbers.append(int(round(change_number / (10 ** i), 2) % 10))elif isinstance(change_number, int):real_numbers = []for i in range(len(format_word), -3, -1):if change_number >= 10 ** i or i < 1:real_numbers.append(int(round(change_number / (10 ** i), 2) % 10))else:'%s can\'t change' % change_numberzflag = 0 # 标记连续0次数，以删除万字，或适时插入零字start = len(real_numbers) - 3change_words = []for i in range(start, -3, -1): # 使i对应实际位数，负数为角分if 0 < real_numbers[start - i] or len(change_words) == 0:if zflag:change_words.append(format_num[0])zflag = 0change_words.append(format_num[real_numbers[start - i]])change_words.append(format_word[i + 2])elif 0 == i or (0 == i % 4 and zflag < 3): # 控制 万/元change_words.append(format_word[i + 2])zflag = 0else:zflag += 1if change_words[-1] not in (format_word[0], format_word[1]):# - 最后两位非"角,分"则补"整"change_words.append("整")return ''.join(change_words)print(Num2MoneyFormat(100523.69))
