我有这个ParkingLot.java
public class ParkingLot {private final int size;private Car[] slots = null;List<String> list = new ArrayList<String>();public ParkingLot(int size) { this.size = size; this.slots = new Car[size];}public List licenseWithAParticularColour(String colour) { for (int i = 0; i < slots.length; i ) { if (slots[i].getColour() == colour) { System.out.println(slots[i].getLicense()); list.add(slots[i].getLicense()); return list; } } return null;}
}
我创建了一个ParkingLotTest.java,如下所示
public class ParkingLotTest {private Car car1;private Car car2;private Car car3;private Ticket ticket1;private Ticket ticket2;private Ticket ticket3;private ParkingLot parkingLot;private List<String> list = new ArrayList<String>();@Beforepublic void intializeTestEnvironment() throws Exception { this.car1 = new Car("1234", "White"); this.car2 = new Car("4567", "Black"); this.car3 = new Car("0000", "Red"); this.parkingLot = new ParkingLot(2); this.ticket1 = parkingLot.park(car1); this.ticket2 = parkingLot.park(car2); this.ticket3 = parkingLot.park(car3); this.list = parkingLot.list;}@Testpublic void shouldGetLicensesWithAParticularColour() throws Exception { assertEquals(, parkingLot.licenseWithAParticularColour("White"));}
}
在上面的测试用例中,我想检查List是否填充了正确的许可证.
1.如何在ParkingLotTest.java中创建一个字段,以便第一个类中的List与第二个类文件中的列表相同.
解决方法:
首先,我认为你不需要在ParkingLot上列出所以你的问题实际上没有多大意义:)
其次,只需在每个测试方法中设置预期结果：
public class ParkingLotTest { //... @Test public void shouldGetLicensesWithAParticularColour() throws Exception { List<Car> expected = new ArrayList<Car>(); expected.add(...); assertEquals(expected, parkingLot.licenseWithAParticularColour("White")); }}
并且不要忘记测试意外值或特殊情况.例如：
@Testpublic void shouldNotGetLicensesWithANullColour() throws Exception { ... assertEquals(expected, parkingLot.licenseWithAParticularColour(null));}@Testpublic void shouldNotGetLicensesWithAnUnknownColour() throws Exception { ... assertEquals(expected, parkingLot.licenseWithAParticularColour("unknown"));}
一些补充说明：
>我不会使用Car []作为插槽,而是使用List< Car>.
>你真的不需要List< String> ParkingLot中的列表(以及licenseWithAParticularColour的当前实现是错误的).
>我会用Enum作为颜色.
来源：/content-1-237301.html
