MySQL中, 如何查询某一天, 某一月, 某一年的数据
今天select * from 表名 where to_days(时间字段名) = to_days(now());昨天SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1近7天SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)近30天SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)本月SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )上一月SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1查询本季度数据select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());查询上季度数据select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));查询本年数据select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());查询上年数据select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));查询当前这周的数据SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());查询上周的数据SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;查询上个月的数据复制代码复制代码select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where pudate between 上月最后一天 and 下月第一天 复制代码复制代码查询当前月份的数据 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')查询距离当前现在6个月的数据select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();查询某个月的数据(查询10月份数据)select * from exam where date_format(starttime,'%Y-%m')='-10'select * from exam where date_format(starttime,'%Y-%m')=date_format('-10-05','%Y-%m')
