方案一：wm_concat函数
select username, id, wmsys.wm_concat(subject) as subject, wmsys.wm_concat(score) as score
from STUDENTSCORES
group by username, id
方案二：listagg函数
select username, id, LISTAGG(subject, ‘-‘) within group(order by subject) as subject, LISTAGG(score, ‘,‘) within group(order by score) as score
from STUDENTSCORES
group by username, id
方案三：常规sql
select username, id, translate(ltrim(subject, ‘/‘), ‘*/‘, ‘*,‘) as subject,translate(ltrim (score, ‘/‘), ‘*/‘, ‘*,‘) as score
from
(select row_number() over (partition by username, id order by username, id, lvl desc) as rn, username, id, subject, score
from
(select username, id, level lvl, sys_connect_by_path (subject, ‘/‘) as subject, sys_connect_by_path (score, ‘/‘) as score
from
(select username, id, subject, score,row_number() over (partition by username,id order by username, id) as num from STUDENTSCORES order by username, id)
connect by username = prior username and id = prior id and num - 1 = prior num))
where rn = 1;
注意：
方案一中默认分隔符为 ‘,’
方案二只适合11g之后的版本
原文：/qqjj/p/12922272.html
