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oracle列转行求和 Oracle行转列和列转行

时间:2019-05-26 01:51:16

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oracle列转行求和 Oracle行转列和列转行

一、行转列

1.1、初始测试数据

表结构:TEST_TB_GRADE

Sql代码:

1 create table TEST_TB_GRADE

2 (

3 ID NUMBER(10) not null,

4 USER_NAME VARCHAR2(20 CHAR),

5 COURSE VARCHAR2(20 CHAR),

6 SCORE FLOAT

7 )

初始数据如下图:

1.2、 如果需要实现如下的查询效果图:

这就是最常见的行转列,主要原理是利用decode函数、聚集函数(sum),结合group by分组实现的,具体的sql如下:

Sql代码:

1 select t.user_name,

2 sum(decode(t.course, '语文', score,null)) as CHINESE,

3 sum(decode(t.course, '数学', score,null)) as MATH,

4 sum(decode(t.course, '英语', score,null)) as ENGLISH

5 from test_tb_grade t

6 group by t.user_name

7 order by t.user_name

1.3、延伸

如果要实现对各门功课的不同分数段进行统计,效果图如下:

具体的实现sql如下:

Sql代码:

01 select t2.SCORE_GP,

02 sum(decode(t2.course, '语文', COUNTNUM,null)) as CHINESE,

03 sum(decode(t2.course, '数学', COUNTNUM,null)) as MATH,

04 sum(decode(t2.course, '英语', COUNTNUM,null)) as ENGLISH

05 from (

06 select t.course,

07 case when t.score <60 then '00-60'

08 when t.score >=60 and t.score <80 then '60-80'

09 when t.score >=80 then '80-100' end as SCORE_GP,

10 count(t.score) as COUNTNUM

11 FROM test_tb_grade t

12 group by t.course,

13 case when t.score <60 then '00-60'

14 when t.score >=60 and t.score <80 then '60-80'

15 when t.score >=80 then '80-100' end

16 order by t.course ) t2

17 group by t2.SCORE_GP

18 order by t2.SCORE_GP

二、列转行

1.1、初始测试数据

表结构: TEST_TB_GRADE2

Sql代码:

1 create table TEST_TB_GRADE2

2 (

3 ID NUMBER(10) not null,

4 USER_NAME VARCHAR2(20 CHAR),

5 CN_SCORE FLOAT,

6 MATH_SCORE FLOAT,

7 EN_SCORE FLOAT

8 )

初始数据如下图:

1.2、 如果需要实现如下的查询效果图:

这就是最常见的列转行,主要原理是利用SQL里面的union,具体的sql语句如下:

Sql代码:

1 select user_name, 'CN_SCORE' COURSE , CN_SCORE as SCORE from test_tb_grade2

2 union

3 select user_name, 'MATH_SCORE' COURSE, MATH_SCORE as SCORE from test_tb_grade2

4 union

5 select user_name, 'EN_SCORE' COURSE, EN_SCORE as SCORE from test_tb_grade2

6 order by user_name,COURSE

也可以利用【insert all into ... select】来实现,首先需要先建一个表TEST_TB_GRADE3:

Sql代码:

1 create table TEST_TB_GRADE3

2 (

3 USER_NAME VARCHAR2(20 CHAR),

4 COURSE VARCHAR2(20 CHAR),

5 SCORE FLOAT

6 )

再执行下面的sql:

Sql代码:

1 insert all

2 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '语文', CN_SCORE)

3 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '数学', MATH_SCORE)

4 into test_tb_grade3(USER_NAME,COURSE,SCORE) values(user_name, '英语', EN_SCORE)

5 select user_name, CN_SCORE, MATH_SCORE, EN_SCORE from test_tb_grade2;

6 commit;

别忘记commit操作,然后再查询TEST_TB_GRADE3,发现表中的数据就是列转成行了。

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