问题补充:
求极限:lim(x→0)[cosx+cos^x+cos3(次方)x+……+cosn(次方)x] /(cosx-1),[n(n+1)]/2,
答案:
=lim[-sinx-2cosxsinx-3cos^2xsinx-…-ncos^(n-1)xsinx]/(-sinx)
=lim[1+2cosx+…ncos^(n-1)x
=1+2+…n
=(1+n)n/2
======以下答案可供参考======
供参考答案1:
题目没抄错吧
时间:2021-02-06 04:34:50
求极限:lim(x→0)[cosx+cos^x+cos3(次方)x+……+cosn(次方)x] /(cosx-1),[n(n+1)]/2,
=lim[-sinx-2cosxsinx-3cos^2xsinx-…-ncos^(n-1)xsinx]/(-sinx)
=lim[1+2cosx+…ncos^(n-1)x
=1+2+…n
=(1+n)n/2
======以下答案可供参考======
供参考答案1:
题目没抄错吧
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