三子棋_井字棋(C语言实现)

率先完成三子就是胜利！具体实现、功能函数定义、函数声明分别放在了三个文件中。从main函数入口开始。啥也也不说了，都在代码里了

运行截图：

一个运行结果：

函数声明在game.h文件

#pragma once//函数声明//游戏逻辑/*1. 玩家选择2. 创建数组，打印棋盘3. 用户下棋,电脑下棋4. 判断输赢，输出结果*/#include <stdio.h>#include <stdlib.h>#include <time.h>#define ROW 3//棋盘(字符数组)的行#define COLUMN 3//棋盘(字符数组)的列//初始化棋盘void initboard(char board[ROW][COLUMN], int row, int column);//菜单void menu();//打印棋盘void Print_board(char board[ROW][COLUMN], int row, int column);//玩家输入void keyboard_player(char board[ROW][COLUMN],int row, int column);//电脑输入void keyboard_pc(char board[ROW][COLUMN],int row, int column);判断给定坐标是否是空格或电脑的棋//int iswhat(char board[ROW][COLUMN], int x, int y);//判断状态/*玩家赢*电脑赢#平局Draw继续Continue*/char ISWIN(char board[ROW][COLUMN], int row, int column);//判断棋盘是否有空格int isfull(char board[ROW][COLUMN], int row, int column);

具体实现在game.c文件

#include "game.h"void game() {//创建棋盘，大小可以自己定义char board[ROW][COLUMN] = {0 };//初始化棋盘initboard(board, ROW, COLUMN);//简单随机，确定谁是欧皇，1是玩家，0是电脑unsigned int ret = rand() % 2;if (ret == 1) {printf("玩家先手!\n");//游戏中玩家和电脑交替下棋，是一个循环do {//玩家输入keyboard_player(board, ROW, COLUMN);//实时打印棋盘和棋子Print_board(board, ROW, COLUMN);//判断棋局的状态if (ISWIN(board, ROW, COLUMN) != 'C') {break;}//电脑输入keyboard_pc(board, ROW, COLUMN);//实时打印棋盘和棋子Print_board(board, ROW, COLUMN);//判断棋局的状态if (ISWIN(board, ROW, COLUMN) != 'C') {break;}} while (1);}else {printf("电脑先手!\n");//游戏中玩家和电脑交替下棋，是一个循环do {//电脑输入keyboard_pc(board, ROW, COLUMN);//实时打印棋盘和棋子Print_board(board, ROW, COLUMN);//判断棋局的状态if (ISWIN(board, ROW, COLUMN) != 'C') {break;}//玩家输入keyboard_player(board, ROW, COLUMN);//实时打印棋盘和棋子Print_board(board, ROW, COLUMN);//判断棋局的状态if (ISWIN(board, ROW, COLUMN) != 'C') {break;}} while (1);}//跳出循环时，棋局一定是有结果了，所以要检索ISWIN函数的返回值确定结果if (ISWIN(board, ROW, COLUMN) == '*') {printf("永远滴神!\n");}else if (ISWIN(board, ROW, COLUMN) == '#') {printf("末日人机了!\n");}else {printf("旗鼓相当的对手!\n");}}int main() {//用于玩家输入的变量int input = -1;//随机数种子，用于电脑的随机下棋坐标生成srand((unsigned)time(NULL));char ch;//一个循环，向玩家展示菜单，玩家输入选择决定循环的进行do {//菜单menu();printf("请输入选择>");scanf("%d", &input);//这个循环用来弥补scanf接受字符数据时会死循环的问题while ((ch = getchar()) != '\n') {//这是一条空语句;}switch (input) {case 1://开始游戏game();break;case 0:printf("游戏退出\n");break;default:printf("选择错误,请重新输入\n");break;}//只有当input是0时循环才结束} while (input);return 0;}

函数定义,在gamefuntion.c文件

//函数定义#include "game.h"//初始化棋盘void initboard(char board[ROW][COLUMN], int row, int column) {int i = 0;for (i = 0; i < ROW; i++) {int j = 0;for (j = 0; j < COLUMN; j++) {board[i][j] = ' ';}}}//菜单void menu() {printf("***************************\n");printf("****** 1.三子棋 ******\n");printf("****** 0.退出******\n");printf("***************************\n");}//打印棋盘void Print_board(char board[ROW][COLUMN], int row, int column) {int i = 0;int j = 0;for (i = 0; i < row; i++) {//棋盘列标if (i == 0) {//棋盘左上角用四个空格填充printf(" ");//列标与棋盘的棋子对齐，考虑到棋盘可能增大到两位数，加一点格式输出for (j = 0; j < column; j++) {printf(" %-2d ", j + 1);}printf("\n");}//棋盘行标与棋子对齐，与列标相似。在每一行只打印一次for (j = 0; j < column; j++) {if (j == 0) {printf(" %-2d ", i + 1);}printf(" %c ", board[i][j]);if (j < column - 1)printf("|");}printf("\n");if (i < row - 1) {//棋盘行标相关的四个空格，只在每行的开始打印for (j = 0; j < column; j++) {if (j == 0) {printf(" ");}printf("---");if (j < column - 1)printf("|");}}printf("\n");}}//玩家输入void keyboard_player(char board[ROW][COLUMN],int row, int column) {printf("请输入三子棋的坐标>");int x, y;char ch;while (1) {scanf("%d%d", &x, &y);while ((ch = getchar()) != '\n') {;}if (x >= 1 && x <= row && y >=1 && y <=column) {if (board[x - 1][y - 1] == ' '){board[x - 1][y - 1] = '*';break;}else {printf("转牛角尖是吧!\n请重新输入>");}}else {printf("输入无效!\n请重新输入>");}}printf("玩家下棋:\n");}//电脑输入void keyboard_pc(char board[ROW][COLUMN], int row, int column) {printf("电脑下棋:\n");int x, y;while (1) {x = rand() % row;y = rand() % column;if (board[x][y] == ' ') {board[x][y] = '#';break;鸡肋的电脑下棋判定判断周围平行的四个//if (x + 1 < ROW && y < COLUMN && iswhat(board, x + 1, y)) {//board[x][y] = '#';//break;//}//if (x - 1 < ROW && y < COLUMN && iswhat(board, x - 1, y)) {//board[x][y] = '#';//break;//}//if (x < ROW && y + 1 < COLUMN && iswhat(board, x, y + 1)) {//board[x][y] = '#';//break;//}//if (x < ROW && y - 1 < COLUMN && iswhat(board, x, y - 1)) {//board[x][y] = '#';//break;//}判断周围对角的四个//if (x + 1 < ROW && y + 1< COLUMN && iswhat(board, x + 1, y + 1)) {//board[x][y] = '#';//break;//}//if (x - 1 < ROW && y - 1 < COLUMN && iswhat(board, x - 1, y - 1)) {//board[x][y] = '#';//break;//}//if (x + 1 < ROW && y - 1 < COLUMN && iswhat(board, x + 1, y - 1)) {//board[x][y] = '#';//break;//}//if (x - 1 < ROW && y + 1 < COLUMN && iswhat(board, x - 1, y + 1)) {//board[x][y] = '#';//break;//}}}}判断给定坐标是否是空格或电脑的棋，是返回1，否则返回0//int iswhat(char board[ROW][COLUMN], int x, int y) {//if (board[x][y] == ' ' || board[x][y] == '#') {//return 1;//}//else {//return 0;//}//}//判断状态/*玩家赢*电脑赢#平局Draw继续Continue*///只判断三子棋下的输赢情况，棋盘增大时、五子棋时此判断方法无效char ISWIN(char board[ROW][COLUMN], int row, int column) {int i = 0;//玩家赢*电脑赢#//每行和每列for (i = 0; i < ROW; i++) {if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ') {return board[i][0];}if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ' ') {return board[0][i];}}//主对角线if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != ' ') {return board[0][0];}//副对角线if (board[2][0] == board[1][1] && board[1][1] == board[0][2] && board[2][0] != ' ') {return board[2][0];}//平局if (isfull(board, row, column)) {return 'D';}//继续return 'C';}//返回1是满了//返回0是未满int isfull(char board[ROW][COLUMN], int row, int column) {int flag = 1;int i = 0;for (i = 0; i < ROW; i++) {int j = 0;for (j = 0; j < COLUMN; j++) {if (board[i][j] == ' ') {flag = 0;break;}}}return flag;}

尝试打印多行多列棋盘：

10行15列：

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